hard20 pts · first answer countsfirmwareuartclocks
Baud rate error from rounding
A UART with 16× oversampling runs from a 16 MHz clock and must use a whole-number divider. You want 115200 baud. What actual baud rate and error do you get?
Discussion 0
Join free to post in the discussion.
Related questions
- UART bytes per secondEmbedded Systems Engineer
- First words read after resetEmbedded Systems Engineer
- Why registers are volatileEmbedded Systems Engineer
- Value of an uninitialised globalEmbedded Systems Engineer
- Where initialised globals come fromEmbedded Systems Engineer
- Signals used by SWDEmbedded Systems Engineer
- Garbage characters on the consoleEmbedded Systems Engineer
- I2C lines sitting at 0 VEmbedded Systems Engineer